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$stmt报错

wehg489
2025-03-31 / 0 评论 / 3 阅读 / 正在检测是否收录...

$stmt = $mysqli->prepare("INSERT INTO complete (part_number, quantity, time) VALUES (?, ?, ?)");
if (!$stmt) {

die("预处理失败: " . $mysqli->error);

}
原stmt
$stmt = $mysqli->prepare("INSERT INTO complete (part_number, quantity, time)

                      VALUES (?, ?, ?) ;
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